[行列解析5.4.P3]

\|x\|_{p_2} \le \|x\|_{p_1} \le n^{\frac{1}{p_1} - \frac{1}{p_2}} \|x\|_{p_2}

[C_{\alpha\beta}] =
\begin{bmatrix}
1 & \sqrt{n} & n \\
1 & 1 & \sqrt{n} \\
1 & 1 & 1
\end{bmatrix}, \quad \\
\alpha \backslash \beta
=
\begin{bmatrix}
1 & 2 & \infty \\
1 & 2 & \infty \\
1 & 2 & \infty
\end{bmatrix}